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1/5(x-2)=1/5(x+6)
We move all terms to the left:
1/5(x-2)-(1/5(x+6))=0
Domain of the equation: 5(x-2)!=0
x∈R
Domain of the equation: 5(x+6))!=0We calculate fractions
x∈R
(5xx/(5(x-2)*5(x+6)))+(-5xx/(5(x-2)*5(x+6)))=0
We calculate terms in parentheses: +(5xx/(5(x-2)*5(x+6))), so:
5xx/(5(x-2)*5(x+6))
We multiply all the terms by the denominator
5xx
Back to the equation:
+(5xx)
We calculate terms in parentheses: +(-5xx/(5(x-2)*5(x+6))), so:We get rid of parentheses
-5xx/(5(x-2)*5(x+6))
We multiply all the terms by the denominator
-5xx
Back to the equation:
+(-5xx)
5xx-5xx=0
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