1/5(x-2)=1/10(1x+6)

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Solution for 1/5(x-2)=1/10(1x+6) equation: 



1/5(x-2)=1/10(1x+6)

We move all terms to the left:

1/5(x-2)-(1/10(1x+6))=0



Domain of the equation: 5(x-2)!=0

x∈R





Domain of the equation: 10(1x+6))!=0

x∈R



We add all the numbers together, and all the variables

1/5(x-2)-(1/10(x+6))=0

We calculate fractions


(10xx/(5(x-2)*10(x+6)))+(-5xx/(5(x-2)*10(x+6)))=0



We calculate terms in parentheses: +(10xx/(5(x-2)*10(x+6))), so:

10xx/(5(x-2)*10(x+6))

We multiply all the terms by the denominator


10xx

Back to the equation:

+(10xx)





We calculate terms in parentheses: +(-5xx/(5(x-2)*10(x+6))), so:

-5xx/(5(x-2)*10(x+6))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

10xx-5xx=0

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