1/5(x-10)=-2/7(14-x)

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Solution for 1/5(x-10)=-2/7(14-x) equation: 



1/5(x-10)=-2/7(14-x)

We move all terms to the left:

1/5(x-10)-(-2/7(14-x))=0



Domain of the equation: 5(x-10)!=0

x∈R





Domain of the equation: 7(14-x))!=0

x∈R



We add all the numbers together, and all the variables

1/5(x-10)-(-2/7(-1x+14))=0

We calculate fractions


(7x(-)/(5(x-10)*7(-1x+14)))+(-(-10xx)/(5(x-10)*7(-1x+14)))=0



We calculate terms in parentheses: +(7x(-)/(5(x-10)*7(-1x+14))), so:

7x(-)/(5(x-10)*7(-1x+14))

We add all the numbers together, and all the variables

7x0/(5(x-10)*7(-1x+14))

We multiply all the terms by the denominator


7x0

We add all the numbers together, and all the variables

7x

Back to the equation:

+(7x)





We calculate terms in parentheses: +(-(-10xx)/(5(x-10)*7(-1x+14))), so:

-(-10xx)/(5(x-10)*7(-1x+14))

We multiply all the terms by the denominator


-(-10xx)

We get rid of parentheses

10xx

Back to the equation:

+(10xx)

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