1/5(x+2)=2x-2(3-x)-5

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Solution for 1/5(x+2)=2x-2(3-x)-5 equation: 


x in (-oo:+oo)

(1/5)*(x+2) = 2*x-(2*(3-x))-5 // - 2*x-(2*(3-x))-5

(1/5)*(x+2)+2*(3-x)-(2*x)+5 = 0

(1/5)*(x+2)+2*(3-x)-2*x+5 = 0

1/5*(x+2)+2*(3-x)-2*x+5 = 0

1/5*(x+2)+2*(3-x)-2*x+5 = 0

5-9/5*x-2*x+32/5 = 0

5-19/5*x+32/5 = 0

57/5-19/5*x = 0

57/5-19/5*x = 0

57/5-19/5*x = 0 // - 57/5

-19/5*x = -57/5 // : -19/5

x = -57/5/(-19/5)

x = 3

x = 3

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