1/5(x+2)=17

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Solution for 1/5(x+2)=17 equation: 



1/5(x+2)=17

We move all terms to the left:

1/5(x+2)-(17)=0



Domain of the equation: 5(x+2)!=0

x∈R



We multiply all the terms by the denominator


-17*5(x+2)+1=0

Wy multiply elements

-85x(x+1=0

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