1/5(x+0.5)+5.24+3/2x+7/10(x=2.2)

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Solution for 1/5(x+0.5)+5.24+3/2x+7/10(x=2.2) equation: 



1/5(x+0.5)+5.24+3/2x+7/10(x=2.2)

We move all terms to the left:

1/5(x+0.5)+5.24+3/2x+7/10(x-(2.2))=0



Domain of the equation: 5(x+0.5)!=0

x∈R





Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 10(x-(2.2))!=0

x∈R



We calculate fractions


20x^2/(5(x+0.5)*2x*10(x-(2.2)))+(150x^2x/(5(x+0.5)*2x*10(x-(2.2)))+(70x^2x/(5(x+0.5)*2x*10(x-(2.2)))+5.24=0

We can not solve this equation

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