1/5(d+2)+5=1/4(2-d)+2

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Solution for 1/5(d+2)+5=1/4(2-d)+2 equation: 



1/5(d+2)+5=1/4(2-d)+2

We move all terms to the left:

1/5(d+2)+5-(1/4(2-d)+2)=0



Domain of the equation: 5(d+2)!=0

d∈R





Domain of the equation: 4(2-d)+2)!=0

d∈R



We add all the numbers together, and all the variables

1/5(d+2)-(1/4(-1d+2)+2)+5=0

We calculate fractions


(4d(-)/(5(d+2)*4(-1d+2))+(-5dd/(5(d+2)*4(-1d+2))+5=0

We can not solve this equation

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