1/5(c-3)=-24

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Solution for 1/5(c-3)=-24 equation: 



1/5(c-3)=-24

We move all terms to the left:

1/5(c-3)-(-24)=0



Domain of the equation: 5(c-3)!=0

c∈R



We add all the numbers together, and all the variables

1/5(c-3)+24=0

We multiply all the terms by the denominator


24*5(c-3)+1=0

Wy multiply elements

120c(c+1=0

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