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1/5(90-x)=x
We move all terms to the left:
1/5(90-x)-(x)=0
Domain of the equation: 5(90-x)!=0We add all the numbers together, and all the variables
x∈R
1/5(-1x+90)-x=0
We add all the numbers together, and all the variables
-1x+1/5(-1x+90)=0
We multiply all the terms by the denominator
-1x*5(-1x+90)+1=0
Wy multiply elements
-5x^2(-+1=0
We use the square of the difference formula
-5x^2(-1=0
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