1/5(5t-1)=1/3(t-2)-1/4(2t-3)

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Solution for 1/5(5t-1)=1/3(t-2)-1/4(2t-3) equation: 


t in (-oo:+oo)

(1/5)*(5*t-1) = (1/3)*(t-2)-((1/4)*(2*t-3)) // - (1/3)*(t-2)-((1/4)*(2*t-3))

(1/5)*(5*t-1)-((1/3)*(t-2))+(1/4)*(2*t-3) = 0

(1/5)*(5*t-1)+(-1/3)*(t-2)+(1/4)*(2*t-3) = 0

1/5*(5*t-1)-1/3*(t-2)+1/4*(2*t-3) = 0

1/5*(5*t-1)-1/3*(t-2)+1/4*(2*t-3) = 0

2/3*t+1/2*t-3/4+7/15 = 0

7/6*t-17/60 = 0

7/6*t-17/60 = 0

7/6*t-17/60 = 0 // + 17/60

7/6*t = 17/60 // : 7/6

t = 17/60/7/6

t = 17/70

t = 17/70

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