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1/5(5h-45)+h=9-2h
We move all terms to the left:
1/5(5h-45)+h-(9-2h)=0
Domain of the equation: 5(5h-45)!=0We add all the numbers together, and all the variables
h∈R
1/5(5h-45)+h-(-2h+9)=0
We add all the numbers together, and all the variables
h+1/5(5h-45)-(-2h+9)=0
We get rid of parentheses
h+1/5(5h-45)+2h-9=0
We multiply all the terms by the denominator
h*5(5h-45)+2h*5(5h-45)-9*5(5h-45)+1=0
Wy multiply elements
5h^2(5+10h^2(5-45h(5+1=0
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