1/5(50)(x2)=225

Solution for 1/5(50)(x2)=225 equation:

1/5(50)(x2)=225

We move all terms to the left:

1/5(50)(x2)-(225)=0


Domain of the equation: 550x2!=0

x^2!=0/550

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-225*550x2+1=0

Wy multiply elements

-123750x^2+1=0

a = -123750; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-123750)·1
Δ = 495000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{495000}=\sqrt{22500*22}=\sqrt{22500}*\sqrt{22}=150\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150\sqrt{22}}{2*-123750}=\frac{0-150\sqrt{22}}{-247500}
=-\frac{150\sqrt{22}}{-247500}
=-\frac{\sqrt{22}}{-1650}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150\sqrt{22}}{2*-123750}=\frac{0+150\sqrt{22}}{-247500}
=\frac{150\sqrt{22}}{-247500}
=\frac{\sqrt{22}}{-1650}
$