1/5(4x+20)+3x=6(x-3)

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Solution for 1/5(4x+20)+3x=6(x-3) equation: 



1/5(4x+20)+3x=6(x-3)

We move all terms to the left:

1/5(4x+20)+3x-(6(x-3))=0



Domain of the equation: 5(4x+20)!=0

x∈R



We add all the numbers together, and all the variables

3x+1/5(4x+20)-(6(x-3))=0

We multiply all the terms by the denominator


3x*5(4x+20)-((6(x-3)))*5(4x+20)+1=0



We calculate terms in parentheses: -((6(x-3)))*5(4x+20), so:

(6(x-3)))*5(4x+20



Wy multiply elements

15x^2(4-((6(x-3)))*5(4x+20)+1=0

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