1/5(4j+2k-6j+3k)

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Solution for 1/5(4j+2k-6j+3k) equation: 


x in (-oo:+oo)

(1/5)*(4*j-(6*j)+2*k+3*k) = 0

(1/5)*(4*j-6*j+2*k+3*k) = 0

1/5*(5*k-2*j) = 0

x belongs to the empty set

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