1/5(3x+12)=2(3-3x)+3

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Solution for 1/5(3x+12)=2(3-3x)+3 equation: 


x in (-oo:+oo)

(1/5)*(3*x+12) = 2*(3-(3*x))+3 // - 2*(3-(3*x))+3

(1/5)*(3*x+12)-(2*(3-(3*x)))-3 = 0

(1/5)*(3*x+12)-2*(3-3*x)-3 = 0

1/5*(3*x+12)-2*(3-3*x)-3 = 0

1/5*(3*x+12)-2*(3-3*x)-3 = 0

33/5*x-18/5-3 = 0

33/5*x-33/5 = 0

33/5*x-33/5 = 0

33/5*x-33/5 = 0 // + 33/5

33/5*x = 33/5 // : 33/5

x = 33/5/33/5

x = 1

x = 1

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