1/5(35d-25)

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Solution for 1/5(35d-25) equation: 


d in (-oo:+oo)

(1/5)*(35*d-25) = 0

1/5*(35*d-25) = 0

( 1/5 )

1/5 = 0

d belongs to the empty set

( 35*d-25 )

35*d-25 = 0 // + 25

35*d = 25 // : 35

d = 25/35

d = 5/7

d = 5/7

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