1/5(30x+40)=-1/2(18x-4)

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Solution for 1/5(30x+40)=-1/2(18x-4) equation: 



1/5(30x+40)=-1/2(18x-4)

We move all terms to the left:

1/5(30x+40)-(-1/2(18x-4))=0



Domain of the equation: 5(30x+40)!=0

x∈R





Domain of the equation: 2(18x-4))!=0

x∈R



We calculate fractions


(2x1/(5(30x+40)*2(18x-4)))+(-(-5x3)/(5(30x+40)*2(18x-4)))=0



We calculate terms in parentheses: +(2x1/(5(30x+40)*2(18x-4))), so:

2x1/(5(30x+40)*2(18x-4))

We multiply all the terms by the denominator


2x1

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-(-5x3)/(5(30x+40)*2(18x-4))), so:

-(-5x3)/(5(30x+40)*2(18x-4))

We add all the numbers together, and all the variables

-(-5x^3)/(5(30x+40)*2(18x-4))

We multiply all the terms by the denominator


-(-5x^3)

We do not support expression: x^3

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