1/5(30x+40)-3=-1/3(15x-9)

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Solution for 1/5(30x+40)-3=-1/3(15x-9) equation: 



1/5(30x+40)-3=-1/3(15x-9)

We move all terms to the left:

1/5(30x+40)-3-(-1/3(15x-9))=0



Domain of the equation: 5(30x+40)!=0

x∈R





Domain of the equation: 3(15x-9))!=0

x∈R



We calculate fractions


(3x1/(5(30x+40)*3(15x-9)))+(-(-5x3)/(5(30x+40)*3(15x-9)))-3=0



We calculate terms in parentheses: +(3x1/(5(30x+40)*3(15x-9))), so:

3x1/(5(30x+40)*3(15x-9))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-5x3)/(5(30x+40)*3(15x-9))), so:

-(-5x3)/(5(30x+40)*3(15x-9))

We add all the numbers together, and all the variables

-(-5x^3)/(5(30x+40)*3(15x-9))

We multiply all the terms by the denominator


-(-5x^3)

We do not support expression: x^3

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