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1/5(25x-5)=2/5(25x-5
We move all terms to the left:
1/5(25x-5)-(2/5(25x-5)=0
Domain of the equation: 5(25x-5)!=0We multiply all the terms by the denominator
x∈R
1-(2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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