1/5(25-10b)+5=1/3(9b-45)-10

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Solution for 1/5(25-10b)+5=1/3(9b-45)-10 equation:



1/5(25-10b)+5=1/3(9b-45)-10
We move all terms to the left:
1/5(25-10b)+5-(1/3(9b-45)-10)=0
Domain of the equation: 5(25-10b)!=0
b∈R
Domain of the equation: 3(9b-45)-10)!=0
b∈R
We add all the numbers together, and all the variables
1/5(-10b+25)-(1/3(9b-45)-10)+5=0
We calculate fractions
(3b9/(5(-10b+25)*3(9b-45))+(-5b0/(5(-10b+25)*3(9b-45))+5=0
We can not solve this equation

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