1/5(2-2/3y)+2y=4/3

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Solution for 1/5(2-2/3y)+2y=4/3 equation: 


y in (-oo:+oo)

(1/5)*(2-((2/3)*y))+2*y = 4/3 // - 4/3

(1/5)*(2-((2/3)*y))+2*y-(4/3) = 0

(1/5)*((-2/3)*y+2)+2*y-4/3 = 0

1/5*(2-2/3*y)+2*y-4/3 = 0

(1/5*3*(2-2/3*y))/3+(2*3*y)/3-4/3 = 0

1/5*3*(2-2/3*y)+2*3*y-4 = 0

28/5*y-4+6/5 = 0

28/5*y-14/5 = 0

(28/5*y-14/5)/3 = 0

(28/5*y-14/5)/3 = 0 // * 3

28/5*y-14/5 = 0

28/5*y-14/5 = 0 // + 14/5

28/5*y = 14/5 // : 28/5

y = 14/5/28/5

y = 1/2

y = 1/2

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