1/5(16b-7)=3b-9

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Solution for 1/5(16b-7)=3b-9 equation: 



1/5(16b-7)=3b-9

We move all terms to the left:

1/5(16b-7)-(3b-9)=0



Domain of the equation: 5(16b-7)!=0

b∈R



We get rid of parentheses

1/5(16b-7)-3b+9=0

We multiply all the terms by the denominator


-3b*5(16b-7)+9*5(16b-7)+1=0

Wy multiply elements

-15b^2(1+45b(1+1=0

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