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1/5(10x-30)=3x-4+x
We move all terms to the left:
1/5(10x-30)-(3x-4+x)=0
Domain of the equation: 5(10x-30)!=0We add all the numbers together, and all the variables
x∈R
1/5(10x-30)-(4x-4)=0
We get rid of parentheses
1/5(10x-30)-4x+4=0
We multiply all the terms by the denominator
-4x*5(10x-30)+4*5(10x-30)+1=0
Wy multiply elements
-20x^2(1+20x(1+1=0
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