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1/5(10x-25)+4x=1/2(8x+2)
We move all terms to the left:
1/5(10x-25)+4x-(1/2(8x+2))=0
Domain of the equation: 5(10x-25)!=0
x∈R
Domain of the equation: 2(8x+2))!=0We add all the numbers together, and all the variables
x∈R
4x+1/5(10x-25)-(1/2(8x+2))=0
We calculate fractions
4x+(2x8/(5(10x-25)*2(8x+2)))+(-5x1/(5(10x-25)*2(8x+2)))=0
We calculate terms in parentheses: +(2x8/(5(10x-25)*2(8x+2))), so:
2x8/(5(10x-25)*2(8x+2))
We multiply all the terms by the denominator
2x8
We add all the numbers together, and all the variables
2x^8
We do not support expression: x^8
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