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1/5(10x+9)=1/5(6-4x)
We move all terms to the left:
1/5(10x+9)-(1/5(6-4x))=0
Domain of the equation: 5(10x+9)!=0
x∈R
Domain of the equation: 5(6-4x))!=0We add all the numbers together, and all the variables
x∈R
1/5(10x+9)-(1/5(-4x+6))=0
We calculate fractions
(5x(-)/(5(10x+9)*5(-4x+6)))+(-5x1/(5(10x+9)*5(-4x+6)))=0
We calculate terms in parentheses: +(5x(-)/(5(10x+9)*5(-4x+6))), so:
5x(-)/(5(10x+9)*5(-4x+6))
We add all the numbers together, and all the variables
5x0/(5(10x+9)*5(-4x+6))
We multiply all the terms by the denominator
5x0
We add all the numbers together, and all the variables
5x
Back to the equation:
+(5x)
We calculate terms in parentheses: +(-5x1/(5(10x+9)*5(-4x+6))), so:We get rid of parentheses
-5x1/(5(10x+9)*5(-4x+6))
We multiply all the terms by the denominator
-5x1
We add all the numbers together, and all the variables
-5x
Back to the equation:
+(-5x)
5x-5x=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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