1/4z-1/2z=1/2-5

Solution for 1/4z-1/2z=1/2-5 equation:

1/4z-1/2z=1/2-5

We move all terms to the left:

1/4z-1/2z-(1/2-5)=0


Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R


We get rid of parentheses

1/4z-1/2z+5-1/2=0

We calculate fractions


8z/32z^2+(-4z)/32z^2+(-4z)/32z^2+5=0

We multiply all the terms by the denominator


8z+(-4z)+(-4z)+5*32z^2=0

Wy multiply elements

160z^2+8z+(-4z)+(-4z)=0

We get rid of parentheses

160z^2+8z-4z-4z=0

We add all the numbers together, and all the variables

160z^2=0

a = 160; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·160·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{320}=0$