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1/4x=5/3x-4=2-1/12x
We move all terms to the left:
1/4x-(5/3x-4)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x-4)!=0We get rid of parentheses
x∈R
1/4x-5/3x+4=0
We calculate fractions
3x/12x^2+(-20x)/12x^2+4=0
We multiply all the terms by the denominator
3x+(-20x)+4*12x^2=0
Wy multiply elements
48x^2+3x+(-20x)=0
We get rid of parentheses
48x^2+3x-20x=0
We add all the numbers together, and all the variables
48x^2-17x=0
a = 48; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·48·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*48}=\frac{0}{96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*48}=\frac{34}{96} =17/48 $
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