1/4x-1=10+x

Solution for 1/4x-1=10+x equation:

1/4x-1=10+x

We move all terms to the left:

1/4x-1-(10+x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

1/4x-(x+10)-1=0

We get rid of parentheses

1/4x-x-10-1=0

We multiply all the terms by the denominator


-x*4x-10*4x-1*4x+1=0

Wy multiply elements

-4x^2-40x-4x+1=0

We add all the numbers together, and all the variables

-4x^2-44x+1=0

a = -4; b = -44; c = +1;
Δ = b2-4ac
Δ = -442-4·(-4)·1
Δ = 1952
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1952}=\sqrt{16*122}=\sqrt{16}*\sqrt{122}=4\sqrt{122}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-4\sqrt{122}}{2*-4}=\frac{44-4\sqrt{122}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+4\sqrt{122}}{2*-4}=\frac{44+4\sqrt{122}}{-8}
$