1/4x+5=x-14

Solution for 1/4x+5=x-14 equation:

1/4x+5=x-14

We move all terms to the left:

1/4x+5-(x-14)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

1/4x-x+14+5=0

We multiply all the terms by the denominator


-x*4x+14*4x+5*4x+1=0

Wy multiply elements

-4x^2+56x+20x+1=0

We add all the numbers together, and all the variables

-4x^2+76x+1=0

a = -4; b = 76; c = +1;
Δ = b2-4ac
Δ = 762-4·(-4)·1
Δ = 5792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5792}=\sqrt{16*362}=\sqrt{16}*\sqrt{362}=4\sqrt{362}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-4\sqrt{362}}{2*-4}=\frac{-76-4\sqrt{362}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+4\sqrt{362}}{2*-4}=\frac{-76+4\sqrt{362}}{-8}
$