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1/4x+3=-5x
We move all terms to the left:
1/4x+3-(-5x)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
1/4x+5x+3=0
We multiply all the terms by the denominator
5x*4x+3*4x+1=0
Wy multiply elements
20x^2+12x+1=0
a = 20; b = 12; c = +1;
Δ = b2-4ac
Δ = 122-4·20·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8}{2*20}=\frac{-20}{40} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8}{2*20}=\frac{-4}{40} =-1/10 $
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