1/4x+3-5=2/3x+7

Solution for 1/4x+3-5=2/3x+7 equation:

1/4x+3-5=2/3x+7

We move all terms to the left:

1/4x+3-5-(2/3x+7)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 3x+7)!=0

x∈R


We add all the numbers together, and all the variables

1/4x-(2/3x+7)-2=0

We get rid of parentheses

1/4x-2/3x-7-2=0

We calculate fractions


3x/12x^2+(-8x)/12x^2-7-2=0

We add all the numbers together, and all the variables

3x/12x^2+(-8x)/12x^2-9=0

We multiply all the terms by the denominator


3x+(-8x)-9*12x^2=0

Wy multiply elements

-108x^2+3x+(-8x)=0

We get rid of parentheses

-108x^2+3x-8x=0

We add all the numbers together, and all the variables

-108x^2-5x=0

a = -108; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-108)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-108}=\frac{0}{-216}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-108}=\frac{10}{-216}
=-5/108
$