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1/4x+26=x+34
We move all terms to the left:
1/4x+26-(x+34)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
1/4x-x-34+26=0
We multiply all the terms by the denominator
-x*4x-34*4x+26*4x+1=0
Wy multiply elements
-4x^2-136x+104x+1=0
We add all the numbers together, and all the variables
-4x^2-32x+1=0
a = -4; b = -32; c = +1;
Δ = b2-4ac
Δ = -322-4·(-4)·1
Δ = 1040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1040}=\sqrt{16*65}=\sqrt{16}*\sqrt{65}=4\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{65}}{2*-4}=\frac{32-4\sqrt{65}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{65}}{2*-4}=\frac{32+4\sqrt{65}}{-8} $
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