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1/4x+2/3x-4=-4+5/2
We move all terms to the left:
1/4x+2/3x-4-(-4+5/2)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/4x+2/3x-4-(5/2-4)=0
We get rid of parentheses
1/4x+2/3x-4+4-5/2=0
We calculate fractions
(-180x^2)/48x^2+12x/48x^2+32x/48x^2-4+4=0
We add all the numbers together, and all the variables
(-180x^2)/48x^2+12x/48x^2+32x/48x^2=0
We multiply all the terms by the denominator
(-180x^2)+12x+32x=0
We add all the numbers together, and all the variables
(-180x^2)+44x=0
We get rid of parentheses
-180x^2+44x=0
a = -180; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·(-180)·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*-180}=\frac{-88}{-360} =11/45 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*-180}=\frac{0}{-360} =0 $
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