1/4x+18+x=1/12(x+36)+13

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Solution for 1/4x+18+x=1/12(x+36)+13 equation: 



1/4x+18+x=1/12(x+36)+13

We move all terms to the left:

1/4x+18+x-(1/12(x+36)+13)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 12(x+36)+13)!=0

x∈R



We add all the numbers together, and all the variables

x+1/4x-(1/12(x+36)+13)+18=0

We calculate fractions


x+(12xx/(48x^2x+(-(1*4x)/(48x^2x+18=0

We can not solve this equation

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