1/4x+10=1/3x+50

Solution for 1/4x+10=1/3x+50 equation:

1/4x+10=1/3x+50

We move all terms to the left:

1/4x+10-(1/3x+50)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 3x+50)!=0

x∈R


We get rid of parentheses

1/4x-1/3x-50+10=0

We calculate fractions


3x/12x^2+(-4x)/12x^2-50+10=0

We add all the numbers together, and all the variables

3x/12x^2+(-4x)/12x^2-40=0

We multiply all the terms by the denominator


3x+(-4x)-40*12x^2=0

Wy multiply elements

-480x^2+3x+(-4x)=0

We get rid of parentheses

-480x^2+3x-4x=0

We add all the numbers together, and all the variables

-480x^2-1x=0

a = -480; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-480)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-480}=\frac{0}{-960}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-480}=\frac{2}{-960}
=-1/480
$