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1/4x+1/6x=200
We move all terms to the left:
1/4x+1/6x-(200)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 6x!=0We calculate fractions
x!=0/6
x!=0
x∈R
6x/24x^2+4x/24x^2-200=0
We multiply all the terms by the denominator
6x+4x-200*24x^2=0
We add all the numbers together, and all the variables
10x-200*24x^2=0
Wy multiply elements
-4800x^2+10x=0
a = -4800; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-4800)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-4800}=\frac{-20}{-9600} =1/480 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-4800}=\frac{0}{-9600} =0 $
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