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1/4x+1/16x=10
We move all terms to the left:
1/4x+1/16x-(10)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 16x!=0We calculate fractions
x!=0/16
x!=0
x∈R
16x/64x^2+4x/64x^2-10=0
We multiply all the terms by the denominator
16x+4x-10*64x^2=0
We add all the numbers together, and all the variables
20x-10*64x^2=0
Wy multiply elements
-640x^2+20x=0
a = -640; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-640)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-640}=\frac{-40}{-1280} =1/32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-640}=\frac{0}{-1280} =0 $
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