1/4t+9=t

Solution for 1/4t+9=t equation:

1/4t+9=t

We move all terms to the left:

1/4t+9-(t)=0


Domain of the equation: 4t!=0

t!=0/4

t!=0

t∈R


We add all the numbers together, and all the variables

-1t+1/4t+9=0

We multiply all the terms by the denominator


-1t*4t+9*4t+1=0

Wy multiply elements

-4t^2+36t+1=0

a = -4; b = 36; c = +1;
Δ = b2-4ac
Δ = 362-4·(-4)·1
Δ = 1312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1312}=\sqrt{16*82}=\sqrt{16}*\sqrt{82}=4\sqrt{82}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{82}}{2*-4}=\frac{-36-4\sqrt{82}}{-8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{82}}{2*-4}=\frac{-36+4\sqrt{82}}{-8}
$