1/4p+8=1/3p

Solution for 1/4p+8=1/3p equation:

1/4p+8=1/3p

We move all terms to the left:

1/4p+8-(1/3p)=0


Domain of the equation: 4p!=0

p!=0/4

p!=0

p∈R



Domain of the equation: 3p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

1/4p-(+1/3p)+8=0

We get rid of parentheses

1/4p-1/3p+8=0

We calculate fractions


3p/12p^2+(-4p)/12p^2+8=0

We multiply all the terms by the denominator


3p+(-4p)+8*12p^2=0

Wy multiply elements

96p^2+3p+(-4p)=0

We get rid of parentheses

96p^2+3p-4p=0

We add all the numbers together, and all the variables

96p^2-1p=0

a = 96; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·96·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*96}=\frac{0}{192}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*96}=\frac{2}{192}
=1/96
$