1/4p(2)-3=-2

Solution for 1/4p(2)-3=-2 equation:

1/4p(2)-3=-2

We move all terms to the left:

1/4p(2)-3-(-2)=0


Domain of the equation: 4p2!=0

p^2!=0/4

p^2!=√0

p!=0

p∈R


We add all the numbers together, and all the variables

1/4p2-1=0

We multiply all the terms by the denominator


-1*4p2+1=0

Wy multiply elements

-4p^2+1=0

a = -4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-4)·1
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-4}=\frac{-4}{-8}
=1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-4}=\frac{4}{-8}
=-1/2
$