1/4n+20=-1/2n-4

Solution for 1/4n+20=-1/2n-4 equation:

1/4n+20=-1/2n-4

We move all terms to the left:

1/4n+20-(-1/2n-4)=0


Domain of the equation: 4n!=0

n!=0/4

n!=0

n∈R



Domain of the equation: 2n-4)!=0

n∈R


We get rid of parentheses

1/4n+1/2n+4+20=0

We calculate fractions


2n/8n^2+4n/8n^2+4+20=0

We add all the numbers together, and all the variables

2n/8n^2+4n/8n^2+24=0

We multiply all the terms by the denominator


2n+4n+24*8n^2=0

We add all the numbers together, and all the variables

6n+24*8n^2=0

Wy multiply elements

192n^2+6n=0

a = 192; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·192·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*192}=\frac{-12}{384}
=-1/32
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*192}=\frac{0}{384}
=0
$