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1/4n+2/5n-5=-3
We move all terms to the left:
1/4n+2/5n-5-(-3)=0
Domain of the equation: 4n!=0
n!=0/4
n!=0
n∈R
Domain of the equation: 5n!=0We add all the numbers together, and all the variables
n!=0/5
n!=0
n∈R
1/4n+2/5n-2=0
We calculate fractions
5n/20n^2+8n/20n^2-2=0
We multiply all the terms by the denominator
5n+8n-2*20n^2=0
We add all the numbers together, and all the variables
13n-2*20n^2=0
Wy multiply elements
-40n^2+13n=0
a = -40; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-40)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-40}=\frac{-26}{-80} =13/40 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-40}=\frac{0}{-80} =0 $
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