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1/4k=3(1/4k+3
We move all terms to the left:
1/4k-(3(1/4k+3)=0
Domain of the equation: 4k!=0
k!=0/4
k!=0
k∈R
Domain of the equation: 4k+3)!=0We calculate fractions
k∈R
4k/16k^2+(-(3(1*4k)/16k^2=0
We add all the numbers together, and all the variables
4k/16k^2+(-(3(+1*4k)/16k^2=0
We multiply all the terms by the denominator
4k+(-(3(+1*4k)=0
We calculate terms in parentheses: +(-(3(+1*4k), so:
-(3(+1*4k
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| n/4+6=14 | | -70+2x=140 | | 13.7=4c=1.7 | | 14(z+3)=14z+22 | | 2.4z=9.6 | | 4u-11=25 | | d/6+6=2 | | -6=10+2w | | -4-5=2n-5 | | 60-16=11x | | -6b-15=-3 | | 222=6x | | 11x-16=60 | | 3(2x+1)=8x–5 | | 3=267−x | | 2=r-44 | | 9n-3=7n+5 | | 16x+-4=-14 | | 21+g=15 | | 5-3y=-20 | | m+67=87 | | 13n-8=34 | | m+4=68 | | 3n+1=2n+60 | | w-18=9 | | 79=t+33 | | j-18=8 | | 273=(2n+3) | | r+74=77 | | -10=-z-5 | | m+4=61 | | 8.7=x=96 |