1/4k-(k+1/3)=1/12(k+4)

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Solution for 1/4k-(k+1/3)=1/12(k+4) equation: 


k in (-oo:+oo)

(1/4)*k-k-(1/3) = (1/12)*(k+4) // - (1/12)*(k+4)

(1/4)*k-((1/12)*(k+4))-k-(1/3) = 0

(-1/12)*(k+4)+(1/4)*k-k-1/3 = 0

k/4-1/12*(k+4)-k-1/3 = 0

(-1/12*3*4*(k+4))/(3*4)+(3*k)/(3*4)+(3*4*(-k))/(3*4)+(-1*4)/(3*4) = 0

3*k-1/12*3*4*(k+4)+3*4*(-k)-1*4 = 0

2*k-12*k-4-4 = 0

-10*k-4-4 = 0

-10*k-8 = 0

(-10*k-8)/(3*4) = 0

(-10*k-8)/(3*4) = 0 // * 3*4

-10*k-8 = 0

-10*k-8 = 0 // + 8

-10*k = 8 // : -10

k = 8/(-10)

k = -4/5

k = -4/5

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