1/4k-(k+1/2)=1/8(k+2)

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Solution for 1/4k-(k+1/2)=1/8(k+2) equation: 


k in (-oo:+oo)

(1/4)*k-k-(1/2) = (1/8)*(k+2) // - (1/8)*(k+2)

(1/4)*k-((1/8)*(k+2))-k-(1/2) = 0

(-1/8)*(k+2)+(1/4)*k-k-1/2 = 0

k/4-1/8*(k+2)-k-1/2 = 0

(-1/8*2*4*(k+2))/(2*4)+(2*k)/(2*4)+(2*4*(-k))/(2*4)+(-1*4)/(2*4) = 0

2*k-1/8*2*4*(k+2)+2*4*(-k)-1*4 = 0

k-8*k-4-2 = 0

-7*k-4-2 = 0

-7*k-6 = 0

(-7*k-6)/(2*4) = 0

(-7*k-6)/(2*4) = 0 // * 2*4

-7*k-6 = 0

-7*k-6 = 0 // + 6

-7*k = 6 // : -7

k = 6/(-7)

k = -6/7

k = -6/7

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