1/4k+2=8(k-1)

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Solution for 1/4k+2=8(k-1) equation: 



1/4k+2=8(k-1)

We move all terms to the left:

1/4k+2-(8(k-1))=0



Domain of the equation: 4k!=0

k!=0/4

k!=0

k∈R



We multiply all the terms by the denominator


-((8(k-1)))*4k+2*4k+1=0

Wy multiply elements

-((8(k-1)))*4k+8k+1=0

We add all the numbers together, and all the variables

8k-((8(k-1)))*4k+1=0

We move all terms containing k to the left, all other terms to the right

8k-((8(k-1)))*4k=-1

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