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1/4a-1/3a=93
We move all terms to the left:
1/4a-1/3a-(93)=0
Domain of the equation: 4a!=0
a!=0/4
a!=0
a∈R
Domain of the equation: 3a!=0We calculate fractions
a!=0/3
a!=0
a∈R
3a/12a^2+(-4a)/12a^2-93=0
We multiply all the terms by the denominator
3a+(-4a)-93*12a^2=0
Wy multiply elements
-1116a^2+3a+(-4a)=0
We get rid of parentheses
-1116a^2+3a-4a=0
We add all the numbers together, and all the variables
-1116a^2-1a=0
a = -1116; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-1116)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-1116}=\frac{0}{-2232} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-1116}=\frac{2}{-2232} =-1/1116 $
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