If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5*x-1*x^3+0*x^2+0 = 0;x
x
e^(x^(2^(2^(1/2))))
{root[3][5.2727]}
e^(x^2)
165.12;68.9
| 5x+6y-2x-7y= | | 4k+10=70 | | 4(3m+2)+5m= | | X=3i*2i | | 13u-9u-4u+2u=12 | | 42=7(s-81) | | 2x+y=33600 | | -7(1x-10)=77 | | 82=2(q-27) | | 32-2y=16 | | 4(x+5)-2=4x+18 | | 18y=72 | | 6x+5x+2x-12x=5 | | 5x-6y-2x+11y-4y= | | 18p+4p-21p-p+4p=8 | | 4p-13=3 | | 5=13-2w | | 25x+2*5x-35=0 | | n+6n-6n=15 | | 2x+6y-2y-9x+4x= | | 1.5*3.14= | | 2/4-2=2 | | 15-2*3/6-3 | | 5r+-12r+10r=-6 | | 4x-(2x+3)=6 | | 204=84-x | | 7=2b-1 | | 11p-9p=14 | | 5y+6x-2y-9x+4x= | | 6x+3=-27-2x | | 5(2z-5)=35 | | 11z-10z+2z=18 |