1/4X+28=2/5x-15

Solution for 1/4X+28=2/5x-15 equation:

1/4X+28=2/5X-15

We move all terms to the left:

1/4X+28-(2/5X-15)=0


Domain of the equation: 4X!=0

X!=0/4

X!=0

X∈R



Domain of the equation: 5X-15)!=0

X∈R


We get rid of parentheses

1/4X-2/5X+15+28=0

We calculate fractions


5X/20X^2+(-8X)/20X^2+15+28=0

We add all the numbers together, and all the variables

5X/20X^2+(-8X)/20X^2+43=0

We multiply all the terms by the denominator


5X+(-8X)+43*20X^2=0

Wy multiply elements

860X^2+5X+(-8X)=0

We get rid of parentheses

860X^2+5X-8X=0

We add all the numbers together, and all the variables

860X^2-3X=0

a = 860; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·860·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*860}=\frac{0}{1720}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*860}=\frac{6}{1720}
=3/860
$