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1/4-1/3x=1/2x
We move all terms to the left:
1/4-1/3x-(1/2x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/3x-(+1/2x)+1/4=0
We get rid of parentheses
-1/3x-1/2x+1/4=0
We calculate fractions
12x^2/96x^2+(-32x)/96x^2+(-48x)/96x^2=0
We multiply all the terms by the denominator
12x^2+(-32x)+(-48x)=0
We get rid of parentheses
12x^2-32x-48x=0
We add all the numbers together, and all the variables
12x^2-80x=0
a = 12; b = -80; c = 0;
Δ = b2-4ac
Δ = -802-4·12·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-80}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+80}{2*12}=\frac{160}{24} =6+2/3 $
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